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IBM C2090-730 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| DB2 Architecture and Components | - DB2 instance and database structure
|
| Database Operations and Utilities | - Data loading and movement
|
| Database Fundamentals | - Relational database concepts
|
| Database Administration Basics | - Backup and recovery basics
|
IBM DB2 9 Family Fundamentals Sample Questions:
Which of the following tools can make recommendations for indexes and/or MQTs to improve the performance of DB2 applications?
- A. Design Advisor
- B. Visual Explain
- C. Performance Advisor
- D. Configuration Assistant
If the following statement is executed:
CREATE TABLE employee
(empid INT NOT NULL GENERATED BY DEFAULT
AS IDENTITY (START WITH 1, INCREMENT BY 5),
name VARCHAR(20),
dept INT CHECK (dept BETWEEN 1 AND 20),
hiredate DATE WITH DEFAULT CURRENT DATE,
salary DECIMAL(7,2),
PRIMARY KEY(empid),
CONSTRAINT cst1 CHECK (YEAR(hiredate) > 2006 OR
Salary > 60500));
Which of the following INSERT statements will fail?
- A. INSERT INTO employee VALUES (20, 'Smith', 5, NULL, 65000.00)
- B. INSERT INTO employee VALUES (15, 'Smith', 5, '01/22/2004', 92500.00)
- C. INSERT INTO employee VALUES (DEFAULT, 'Smith', 10, '11/18/2004', 60250.00)
- D. INSERT INTO employee VALUES (DEFAULT, 'Smith', 2, '10/07/2002', 80250.00)
Given the following CREATE TABLE statement:
CREATE TABLE EMPLOYEE
(EMPNO CHAR(3) NOT NULL,
FIRSTNAME CHAR(20) NOT NULL,
MIDINIT CHAR(1),
LASTNAME CHAR(20) NOT NULL,
SALARY DECIMAL(10, 2))
Which of the following will retrieve the rows that have a missing value in the MIDINIT column?
- A. SELECT * FROM employee WHEREmidinit = " "
- B. SELECT * FROM employee WHEREmidinit = NULL
- C. SELECT * FROM employee WHEREmidinit = ' '
- D. SELECT * FROM employee WHEREmidinit IS NULL
Given the following two tables:
TAB1
COL_1 COL_2
A 10 B 12 C 14
TAB2
COL_A COL_B
A 21 C 23 D 25
Assuming the following results are desired:
COL_1 COL_2 COL_A COL_B A 10 A 21 B 12 - C 14 C 23 - - D 25
Which of the following joins will produce the desired results?
- A. SELECT * FROM tab1 LEFT OUTER JOIN tab2 ON col_1 =col_a
- B. SELECT * FROM tab1 INNER JOIN tab2 ON col_1 =col_a
- C. SELECT * FROM tab1 FULL OUTER JOIN tab2 ON col_1 =col_a
- D. SELECT * FROM tab1 RIGHT OUTER JOIN tab2 ON col_1 =col_a
Given the following two tables:
EMPLOYEE
ID NAME DEPTID
01 Mick Jagger 10 02 Keith Richards 20 03 Ronnie Wood 20 04 Charlie Watts 20 05 Bill Wyman 30 06 Brian Jones
DEPARTMENT
ID DEPTNAME
10 Executive Staff 20 Sales 30 Marketing 40 Engineering 50 Human Resources
Which two of the following queries will display the employee name and department name for all employees that are in Sales?
- A. SELECT e.name,d.deptname FROM employee e, department d WHERE e.deptid = d.id AND d.id = '20'
- B. SELECT e.name,d.deptname FROM employee e FULL OUTER JOIN department d ON e.deptid = d.id WHERE d.id = '20'
- C. SELECT e.name,d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE d.id = '20'
- D. SELECT e.name,d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE d.id = '20'
- E. SELECT e.name,d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id
WHERE d.id = '20'
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